2-methylbutan-1-ol is oxidised by potassium dichromate:
2-methylbutan-1-ol + [O] ==> 2-methylbutan-1-al + water
CH3CH2CH(CH3)CH2OH + [O] ==> CH3CH2CH(CH3)CHO + H2O
second step:
CH3CH2CH(CH3)CHO + [O] ==> CH3CH2CH(CH3)COOH
2-methylbutan-1-al + [O] ==> 2-methylbutanoic acid
1) Draw all of the above as displayed formula.
2) What are the two products of the reaction above?
1)
----H--H--CH3--H
-----I----I----I----I --------------------------------------------------- how do I draw the
H - C - C - C - C - O - H -- + how do I draw the [O] ==> 2-methylbutan-1-al
-----I-----I----I----I ----------------------------------------------------------+ water
----H----H---H---H
second step:
how do I draw the --- how do I draw the
2-methylbutan-1-al --------- [O] ----------------
==>
-----H--H---H
------I---I----I
H - C - C - C - COOH
-----I----I----I
-----H--H-CH3
2) Are the two products:
2-methylbutan-1-al + water
2-methylbutanoic acid
There are three products so why are they asking for two as if there are two?
Also, COOH equations look like below at the COOH part:
--------O
-------//
H - C
-------\
--------OH
Methanoic acid
I drew 2-methylbutanoic acid below differently:
-----H--H---H
------I---I----I
H - C - C - C - COOH
-----I----I----I
-----H--H-CH3
Can the COOH part of this displayed formula be like methanoic acid's displayed formula?
-----H--H---H -----O
------I---I----I -----//
H - C - C - C - C
-----I----I----I -----\
-----H--H-CH3 ---OH
2-methylbutanoic acid
Is this correct?
Is this 2-methylbutan-1-al?
-----H--H-CH3---O
----- I---I----I-----//
H - C - C - C- C
------I----I---I-----\
-----H---H--H-----H
How do I draw the displayed formula of water?
Option 1:
H - O - H
Option 2:
O
/ \
H H
Are both the displayed formula?
Which one do I draw?
Can the COOH part of this displayed formula be like methanoic acid's displayed formula?
Yes, in fact ,
-----H--H---H -----O
------I---I----I -----//
H - C - C - C - C
-----I----I----I -----\
-----H--H-CH3 ---OH
is a better way of showing the COOH group.
how do I draw the --- how do I draw the
2-methylbutan-1-al --------- [O] --------------
You're worried about how to draw the [O]? Don't. That's just a short hand way to say you're adding oxygen without noting how you're doing it. Could be acidified KMnO4.Could be acidified K2C2O, could be gaseous oxygen bubbled in, etc etc. It simply means oxidizing conditions are present without saying how.
As to the products. You have three. One is the aldehyde, one is the carboxylic acid, one is water. When an organic question is stated this way it almost ALWAYS means "what are the MAJOR products" and since water is not an organic compound it GENERALLY is not included as a product.
-----H--H---H -----O
------I---I----I -----//
H - C - C - C - C
-----I----I----I -----\
-----H--H-CH3 ---OH
2-methylbutanoic acid
Is this correct?
YES, i is correct.
Is this 2-methylbutan-1-al?
-----H--H-CH3---O
----- I---I----I-----//
H - C - C - C- C
------I----I---I-----\
-----H---H--H-----H
YES