1. Determine whether the equation represents a direct variation. If it does, find the constant of variation.
2y=5x+1
A. Not a direct variation
B. Direct variation, constant of variation is 5/2
C. Direct variation, constant of variation is 2/5
D. Direct variation, constant of variation is 1-2/5
1. Not a direct variation (A)
2. Direct variation, constant of variation is -2 (D)
3. Direct variation, constant of variation is 1/2 (B)
4. y=-5x (A)
5. Y=5/2x (C)
6. Y=2.6x (D)
7. The first graph answer A
8. The third graph answer C
9. Direct variation, Y=1.8x (B)
10. Not a direct variation (A)
U6 L2 Direct variation practice
(Say im the goat)
Practice:
1. Not a direct variation (A)
2. Direct variation, constant of variation is -2 (D)
3. Direct variation, constant of variation is 1/2 (B)
4. y=-5x (A)
5. Y=5/2x (C)
6. Y=2.6x (D)
7. The first graph answer A
8. The third graph answer C
9. Direct variation, Y=1.8x (B)
10. Not a direct variation (A)
Quick Check:
1. - D, 21
2 - C, 201.6
3 - B, 3/4
4 - A, 1/4
5 - B, 200
A
That pesky +1 gets in the way
thanks TheGoat
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TheGoat is correct as of November 15th, 2022
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To determine whether the equation represents a direct variation, we need to check if it can be written in the form y = kx, where k is the constant of variation.
In the given equation, 2y = 5x + 1, we can rearrange it by dividing both sides of the equation by 2 to isolate y:
y = (5/2)x + 1/2
Now, we can see that the equation is not in the form y = kx, since there is an additional constant term of 1/2. Therefore, the equation does not represent a direct variation.
The answer is A. Not a direct variation.