Questions LLC
Login
or
Sign Up
Ask a New Question
Math
Calculus
Find area of the region under the curve y=3−5x^2 and above the x-axis.
area =
1 answer
Since the curve crosses the x-axis at x = ±√(3/5), and is symmetric, the area is
2∫[0,√(3/5)] (3-5x^2) dx = 4√(3/5)
You can
ask a new question
or
answer this question
.
Related Questions
R is the first quadrant region enclosed by the x-axis, the curve y = 2x + a, and the line x = a, where a > 0. Find the value of
1. Let R be the region bounded by the x-axis, the graph of y=sqr(x) , and the line x=4 .
a. Find the area of the region R. b.
1. Consider the curve y = f(x) = 2^x - 1.
A. Find the exact area of the region in the first quadrant bounded by the curves y =
Use a graph to give a rough estimate of the area of the region that lies beneath the given curve. Then find the exact area.
y = 6
Point P in the curve y=x^3 has coordinates (3,27) and PQ is the tangent to the curve at P.Point Q touches the x-axis.Find the
R is the region below the curve y=x and above the z-axis from x=0 to x=b, where b is a positive constant. S is the region below
Region R is bounded by the functions f(x) = 2(x-4) + pi, g(x) = cos^-1(x/2 - 3), and the x axis.
a. What is the area of the
1. Let R be the region in the first quadrant enclosed by the graphs of y=4-X , y=3x , and the y-axis.
a. Find the area of region
Hello! I'm having trouble understanding how I'm supposed to work out this problem. Any help would be appreciated!
Find the area
3). The shaded region is bounded by the y-axis and the graphs of y=1+√x, y=2. Find the volume of the solid obtained by