A body weight 0.30N in air,0.25, when fully immersed in water and 0.27 when fully immersed in liquid.
1) calculate it's loss in weight in water
2)it's R.d
3)the R.d of the liquid
To calculate the required values, we need to understand the concepts of weight, density, and relative density (R.d).
1) To calculate the loss in weight in water, we subtract the weight of the body in water from its weight in air.
Loss in weight in water = Weight in air - Weight in water
Weight in air = 0.30N
Weight in water = 0.25N
Substituting these values into the equation, we can calculate the loss in weight in water:
Loss in weight in water = 0.30N - 0.25N = 0.05N
Therefore, the loss in weight of the body in water is 0.05N.
2) Relative density (R.d), also known as specific gravity, is the ratio of the density of a substance to the density of a reference substance. In this case, we use water as the reference substance. The formula for R.d is:
R.d = Density of substance / Density of water
Since we don't have the density of the substance, we cannot directly calculate its R.d without further information. However, we can indirectly calculate it by using the loss in weight in water.
R.d = Weight in air / Loss in weight in water (since the loss in weight is equal to the buoyant force)
Substituting the given values:
R.d = 0.30N / 0.05N = 6
Therefore, the R.d of the body is 6.
3) To calculate the R.d of the liquid, we need the weight of the body when fully immersed in the liquid. However, this information is missing. Without the weight of the body in the liquid, we cannot directly calculate the R.d of the liquid.