Find the resultant of two vectors of 3units and 4units acting at a point o at an angle 45° with each other

let the u=4N force be along the +x axis, so u = 4i

Then v = 3cos45° i + 3sin45°j
Then
u+v = (4+3/√2)i + 3/√2 j
at an angle θ where tanθ = (3/√2) / (4+3/√2)
That is,
u+v = 6.48 at an angle of 19.1°