A toy car, with mass of 2 Kg, is pushed with a force of 8 N. If the toy car is in the grass with a coefficient of friction of 0.1 then what is the acceleration? How far does it get pushed in 2 s?
To find the acceleration of the toy car, we can begin by calculating the net force acting on it. The net force can be determined using Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a):
F = m * a
Given that the mass (m) of the toy car is 2 kg and the force (F) acting on it is 8 N, we can rearrange the formula to solve for acceleration (a):
a = F / m
Substituting the given values:
a = 8 N / 2 kg
a = 4 m/s^2
The acceleration of the toy car is 4 m/s^2.
Next, to determine how far the toy car gets pushed in 2 seconds, we can use the equation for distance traveled (d) with constant acceleration (a) and initial velocity (v0):
d = v0 * t + (1/2) * a * t^2
However, in this case, the initial velocity (v0) is not given. Therefore, we can assume that the car starts from rest, so the initial velocity is 0 m/s. Thus, the equation simplifies to:
d = (1/2) * a * t^2
Substituting the known values:
d = (1/2) * 4 m/s^2 * (2 s)^2
d = (1/2) * 4 m/s^2 * 4 s^2
d = 4 m
Therefore, the toy car gets pushed a distance of 4 meters in 2 seconds.