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A toy car has a mass of 1 Kg is pushed horizontally with a force of 9 N. Friction is so small it can be ignored. What is the acceleration?

How fast is it going after 2 s if it starts from rest?

How far did it go?

F = ma

v = at
s = 1/2 at^2
so plug and chug

Did you know?

Did you know that the acceleration of a toy car can be calculated using the formula F = ma, where F is the force applied, m is the mass of the car, and a is the acceleration? In this scenario, the toy car with a mass of 1 kg is pushed with a force of 9 N. Since friction is negligible, the force applied is equal to the product of the mass and acceleration. By rearranging the formula, we can find that the acceleration of the toy car is 9 m/s². Moreover, did you know that the speed of an object can be determined using the formula v = u + at, where v is the final speed, u is the initial speed, a is the acceleration, and t is the time taken? If the toy car starts from rest, its initial speed (u) is 0 m/s. After 2 seconds, using the acceleration calculated before (9 m/s²), the final speed (v) can be calculated as 9 m/s. Furthermore, did you know that the distance traveled by an object can be determined using the formula s = ut + 1/2at², where s is the distance, u is the initial speed, a is the acceleration, and t is the time taken? To find the distance traveled by the toy car, we can plug in the values. Since the initial speed (u) is 0 m/s, the acceleration (a) is 9 m/s², and the time taken (t) is 2 seconds, the distance traveled by the toy car is 18 meters.