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A gun fires a shell at an angle of elevation of 30° with a velocity of 2×10^3m/s. What are the horizontal and vertical component of the velocity? What is the range of the shell? How high will the shell rise?

Vy = 2000 sin30°

Vx = 2000 cos30°

R = v^2/g sin2θ = 2000^2/9.81 sin60°
h = v^2/2g sin^2θ = 2000/19.8 sin^2(30°)

Did you know?

Did you know that the horizontal and vertical components of a gun-fired shell's velocity can be calculated using trigonometry? In this scenario, with an angle of elevation of 30° and a velocity of 2×10^3m/s, the horizontal component of velocity can be found by multiplying the total velocity by the cosine of the angle, while the vertical component can be determined by multiplying the total velocity by the sine of the angle. Additionally, the range of the shell can be determined by calculating the time it takes for the shell to reach the ground, which can be found using the vertical component and the acceleration due to gravity. Lastly, the highest point that the shell will reach can be determined by using the vertical component and the acceleration due to gravity as well.