A velocity of mangnitude 40m/s is directed at an angle of 45 degree east of North
To find the horizontal and vertical components of the velocity, we can use trigonometry.
Let's assume that North is the positive y-direction and East is the positive x-direction.
Given:
Magnitude of velocity (V) = 40 m/s
Angle (θ) = 45 degrees east of North
To find the horizontal component (Vx) and vertical component (Vy), we can use the following equations:
Vx = V * cos(θ)
Vy = V * sin(θ)
Now let's plug in the values:
Vx = 40 m/s * cos(45 degrees)
Vy = 40 m/s * sin(45 degrees)
Using a calculator:
Vx ≈ 28.28 m/s (rounded to two decimal places)
Vy ≈ 28.28 m/s (rounded to two decimal places)
Therefore, the velocity has a horizontal component of approximately 28.28 m/s to the east (positive x-direction) and a vertical component of approximately 28.28 m/s to the north (positive y-direction).