calculate the concentration of an acetic acid solution prepared by mixing 13.5ml of 10.0M acetic acid with 250.0ml
of 0.15M NaCl solution
10.0 M x [(13.5 mL)/(13.5 + 250.0)] = 10.0 x (13.5/263.5) = ? M
To calculate the concentration of the acetic acid solution, we need to use the concept of moles and the equation for dilution.
1. Calculate the number of moles of acetic acid used:
Moles of acetic acid = volume (in liters) × concentration (in moles per liter)
Since the volume is given in milliliters, we need to convert it to liters.
13.5 ml = 13.5 ÷ 1000 = 0.0135 L
Moles of acetic acid = 0.0135 L × 10.0 M = 0.135 moles
2. Calculate the volume of the final solution:
We are mixing the acetic acid with the NaCl solution, so the volume of the final solution will be the sum of the volumes of both components.
Volume of final solution = volume of acetic acid + volume of NaCl solution
Volume of NaCl solution = 250.0 ml = 250.0 ÷ 1000 = 0.250 L
Volume of final solution = 0.0135 L + 0.250 L = 0.2635 L
3. Calculate the concentration of the final solution:
Concentration = moles/volume
Concentration = 0.135 moles ÷ 0.2635 L = 0.512 M
Therefore, the concentration of the acetic acid solution prepared by mixing 13.5 ml of 10.0M acetic acid with 250.0 ml of 0.15M NaCl solution is 0.512 M.
To calculate the concentration of the acetic acid solution, you can use the formula:
C1V1 = C2V2
Where:
C1 = concentration of initial solution (acetic acid solution)
V1 = volume of initial solution (acetic acid solution)
C2 = concentration of final solution (acetic acid + NaCl solution)
V2 = volume of final solution (acetic acid + NaCl solution)
In this case:
C1 = 10.0 M (concentration of acetic acid solution)
V1 = 13.5 mL (volume of acetic acid solution)
C2 = unknown
V2 = 13.5 mL + 250.0 mL = 263.5 mL (sum of volumes of acetic acid solution and NaCl solution)
Using the formula, we can rearrange it to solve for C2:
C2 = (C1 * V1) / V2
Plugging in the values:
C2 = (10.0 M * 13.5 mL) / 263.5 mL
C2 = 0.51 M
Therefore, the concentration of the acetic acid solution after mixing is approximately 0.51 M.