A tennis ball is dropped from 1.13 m above the
ground. It rebounds to a height of 0.996 m.
With what velocity does it hit the ground?
The acceleration of gravity is 9.8 m/s
2
. (Let
down be negative.)
Answer in units of m/s.
(1/2) m v^2 = m g h
v = -sqrt (2 g h) = -sqrt (2 * 9.8 * 0.996 )
v = -4.42 m/s