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A 4-digit pin code can begin with any number except 0,1 & 2. If repetition of the same

digit is allowed, the probability of a pin code begin with 5 and end with a 3 is?

there are 7*10^3 pin codes

there are 1*10^2*1 of the form 5xx3
so P(5xx3) = 100/7000 = 1/70

Did you know?

Did you know that a 4-digit pin code can begin with any number except 0, 1, and 2? This means that there are 7 possible options for the first digit. Additionally, if repetition of the same digit is allowed, there are 10 options for each subsequent digit. To determine the probability of a pin code beginning with 5 and ending with 3, we need to consider that the first digit must be 5 and the last digit must be 3. With repetition allowed, there are 10 options for the second and third digits. Therefore, the total number of possible pin codes that begin with 5 and end with 3 is 1 x 10 x 10 x 1 = 100. Since there are a total of 7 x 10 x 10 x 10 = 7000 possible pin codes without any restrictions, the probability of a pin code beginning with 5 and ending with 3 is 100/7000 = 1/70, or approximately 0.014289.