Barium can be analyzed by precipitating it as BaSO4 and determining the mass of the precipitate. When a 0.354g sample of a barium compound was treated with excess sulfuric acid, 0.0891g of BaSO4 formed. What percentage of Barium is in the compound?
0.0891 g BaSO4 x (1 mol Ba/1 mol BaSO4) = 0.0891 x (137.3/233.3) = ? g Ba in the sample.
% Ba = (mass Ba in the sample/mass sample)*100 = ?