The 4th and 7th term of a GP are 16 and 2 respectively.
Find.
(a) the 1st term.
(b) the common ratio.
(c) the sum of the first 3 terms.
r^3 = 2/16 = 1/8
so r = 1/3
a = 16/r^3 = 16*27 = ____
...
Find.
(a) the 1st term.
(b) the common ratio.
(c) the sum of the first 3 terms.
so r = 1/3
a = 16/r^3 = 16*27 = ____
...