An object is thrown straight upward from the edge of a building with a velocity of 20 ms-1. Where will the object be 5 s after it was thrown

g/2 = 4.9 m/s^2

h = Hi + Vi t - 4.9 t^2
h = H building + 20 * 5 - 4.9 * 25
= Hbuilding + 100 - 122.6
22.6 meters below the building edge if it did not hit your calculator