A block is pushed with a force of 15 newtons and accelerates at a rate of 3.0 m/s2. How much force would be needed to accelerate the same block at a rate of 6.0 m/s2?

A.7.5 N

B.15 N

C. 30 N

D. 90 N

Well, well, well, looks like we've got a question about force and acceleration! Now, to figure out the answer, we can use Newton's second law, which states that force is equal to mass times acceleration.

So, let's say the mass of the block is 'm'. In the first scenario, the force is 15 newtons and the acceleration is 3.0 m/s^2. That means we have 15 = m * 3.0.

To find out the force required for an acceleration of 6.0 m/s^2, we need to solve for 'm' again. So, if we plug in the new acceleration into the equation, we get force = m * 6.0.

Now, here comes the tricky part! Since we're trying to find the amount of force needed, we must keep the mass constant. Therefore, we can set the two equations equal to each other to solve for force:

m * 3.0 = m * 6.0.

If we simplify this, we get 3.0 = 6.0.

Uh-oh! It seems I made a mistake in my calculations. This equation doesn't make any sense! So, I apologize, but it looks like I can't provide you with a specific answer here.

To find the force needed to accelerate the block at a rate of 6.0 m/s^2, we can use Newton's second law of motion, which states that the force (F) is equal to the mass (m) multiplied by the acceleration (a).

Given:
Force (F1) = 15 N
Acceleration (a1) = 3.0 m/s^2

Let's assume the mass of the block is 'm'.

Using F = ma, we can rearrange the equation to solve for mass:
m = F1 / a1

Substituting the given values:
m = 15 N / 3.0 m/s^2
m = 5 kg (kilograms)

Now, we can find the force (F2) needed to accelerate the block at a rate of 6.0 m/s^2 using the same mass of 5 kg:
F2 = m * a2

Substituting the values:
F2 = 5 kg * 6.0 m/s^2
F2 = 30 N

Therefore, the force needed to accelerate the same block at a rate of 6.0 m/s^2 is 30 Newtons. The answer is C. 30 N.

To find the force needed to accelerate the block at a different rate, we can use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a).

Given:
Force (F₁) = 15 N (force used to accelerate the block at 3.0 m/s²)
Acceleration (a₁) = 3.0 m/s²

We need to find the force (F₂) required to accelerate the same block at a rate of 6.0 m/s².

Since the mass of the block is not given, we can assume that it is constant in both cases, meaning it cancels out when we compare the forces.

We can set up a proportion to solve for F₂:

F₁ / a₁ = F₂ / a₂

Plugging in the known values:
15 N / 3.0 m/s² = F₂ / 6.0 m/s²

Cross-multiplying the equation:
15 N * 6.0 m/s² = 3.0 m/s² * F₂

90 N·m/s² = 3.0 m/s² * F₂

Simplifying:
90 N·m/s² = F₂ * 3.0 m/s²

Dividing both sides by 3.0 m/s²:
90 N·m/s² / 3.0 m/s² = F₂

30 N = F₂

Therefore, the force needed to accelerate the block at a rate of 6.0 m/s² is 30 N.

The correct answer is C. 30 N.

F = ma

twice the acceleration means twice the force