Use the chemical reaction to answer the question.
CaCO3→CO2+CaO
A scientist heats 30 grams of calcium carbonate (CaCO3) in the chemical reaction shown. What is the total mass of the products?
(1 point)
Law of conservation of mass.
mass CO2 + mass CaO = 30 g products = mass reactants = 30 g CaCO3.
You can prove this by stoichiometry .
mols CaCO3 = grams/molar mass = 30/100 = 0.30
1 mole CaCO3 forms 1 mols CaO so 0.30 mols CaO.
grams CaO = moles CaO x molar mass CaO = 0.30 x 56 = 16.8 g
1 mol CaCO3 forms 1 mol CO2 = 0.30 mols CO2 formed.
grams CO2 = mols x molar mass = 0.30 x 44 = 13.2 g
total mass products = 16.8 + 13.2 = 30
mass reactants = 30 g = mass products
What goes in must come out.
To find the total mass of the products, we need to calculate the molar masses of each product and then multiply it by the corresponding coefficient from the balanced equation.
The molar mass of CO2 (carbon dioxide) is 44.01 g/mol, and the coefficient in the balanced equation is 1.
The molar mass of CaO (calcium oxide) is 56.08 g/mol, and the coefficient in the balanced equation is also 1.
Therefore, the total mass of the products can be calculated as follows:
Mass of CO2 = 44.01 g/mol × 1 mol = 44.01 g
Mass of CaO = 56.08 g/mol × 1 mol = 56.08 g
Total mass of the products = Mass of CO2 + Mass of CaO
Total mass of the products = 44.01 g + 56.08 g
Total mass of the products = 100.09 g
Therefore, the total mass of the products is 100.09 grams.
To find the total mass of the products in the chemical reaction, we need to calculate the molar masses of carbon dioxide (CO2) and calcium oxide (CaO) and then determine the amount of each product formed.
First, let's calculate the molar masses of CO2 and CaO:
- Carbon dioxide (CO2):
Carbon (C) has a molar mass of 12.01 g/mol.
Oxygen (O) has a molar mass of 16.00 g/mol.
Multiply the molar mass of carbon by 1 and the molar mass of oxygen by 2 since there are two oxygen atoms in a molecule of CO2.
The molar mass of CO2 = (12.01 g/mol * 1) + (16.00 g/mol * 2) = 44.01 g/mol.
- Calcium oxide (CaO):
Calcium (Ca) has a molar mass of 40.08 g/mol.
Oxygen (O) has a molar mass of 16.00 g/mol.
Multiply the molar mass of calcium by 1 and the molar mass of oxygen by 1 since there is one calcium atom and one oxygen atom in a molecule of CaO.
The molar mass of CaO = (40.08 g/mol * 1) + (16.00 g/mol * 1) = 56.08 g/mol.
Now, let's determine the moles of each product formed:
- Carbon dioxide (CO2):
From the balanced chemical equation, we know that one mole of CaCO3 produces one mole of CO2.
To calculate the moles of CO2, we divide the given mass of CaCO3 (30 grams) by its molar mass (100.09 g/mol).
Moles of CO2 = 30 g / 100.09 g/mol = 0.2999 mol.
- Calcium oxide (CaO):
From the balanced chemical equation, we know that one mole of CaCO3 produces one mole of CaO.
To calculate the moles of CaO, we use the same calculation as for CO2.
Moles of CaO = 30 g / 100.09 g/mol = 0.2999 mol.
Finally, let's calculate the total mass of the products:
The total mass of the products is the sum of the masses of CO2 and CaO formed.
Mass of CO2 = Moles of CO2 * Molar mass of CO2 = 0.2999 mol * 44.01 g/mol = 13.20 g.
Mass of CaO = Moles of CaO * Molar mass of CaO = 0.2999 mol * 56.08 g/mol = 16.82 g.
Therefore, the total mass of the products is 13.20 g (CO2) + 16.82 g (CaO) = 30.02 grams (approximately).