List the total number of each type of atoms in the following reactants.
A) 2HCL + Ca(OH)2
B) 2Na3PO3 + 3Ca(NO3)2
This one is a bit more complicated. May any chemistry teacher show me how to do this. Thank you very much in advance.
Here are the rules:
1. The coefficient multiplies everything in the molecule that follows.
2. The subscript multiples the atom that precedes it UNLESS the subscript follows parentheses in which case EVERY atom within the parentheses is multiplied by the subscript.
2HCL + Ca(OH)2
So rule 1 tells you there are 2 H atoms and 2 Cl atoms in HCl. Rule 1 tells you there is 1 Ca atom and rule 2 tells you there are 2 O aotms and 2 H atoms in 1 mole Ca(OH)2.
2Na3PO3 + 3Ca(NO3)2
There are 3 atoms of Na from the Na3 part and 2 times that from the 2Na3 to make 6 atoms of Na. There are 2 P atoms and 3*2 = 6 O atoms in Na3PO3.
In 3Ca(NO3)2 there are 3 Ca atoms, 1*2*3 = 6 atoms of N and 3*2*3 = 18 atoms of O.
If you wish to post one or two compounds and your answer I shall be happy to check your answers.