What is the value of x in the equation 32(4x – 1) – 3x = 54 – (x + 2)?
32(4x – 1) – 3x = 54 – (x + 2)
just do the usual ...
128x - 32 - 3x = 54 - x - 2
126x = 84
x = 84/128 = 2/3
To solve for the value of x in the equation 32(4x – 1) – 3x = 54 – (x + 2), we can follow these steps:
Step 1: Distribute the coefficients:
32 * 4x = 128x
32 * (-1) = -32
-3x = -3x
54 - (x + 2) = 54 - x - 2 = 52 - x
After distributing, the equation becomes:
128x - 32 - 3x = 52 - x
Step 2: Combine like terms on both sides of the equation:
128x - 3x - x = 52 + 32
Simplifying the equation:
125x - x = 84
Step 3: Combine like terms:
124x = 84
Step 4: Solve for x by dividing both sides of the equation by 124:
x = 84 / 124
Simplifying the fraction:
x = 21 / 31
So, the value of x in the equation is 21/31.