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How much work can be done by a 75% efficient electric motor drawing 2A from a

120 V source for 8 hours?

2 amps * 120 V * 8 hr * 3600 seconds/hr = 6,912,000 Joules

6,912,000 Joules * 0.75 = 5,184,000 Joules

Did you know?

Did you know that the efficiency of an electric motor determines how much work it can accomplish? In this case, a 75% efficient electric motor drawing 2A from a 120V source for 8 hours can do a certain amount of work. The efficiency of 75% means that only three-quarters of the electrical energy will be converted into useful work, while the rest is lost as waste heat. Therefore, to calculate the work done, we need to multiply the energy consumed by the efficiency. In this scenario, the motor would consume 2A x 120V x 8 hours = 1920 watt-hours of energy. However, since the motor is only 75% efficient, the actual work done would be 1920 watt-hours x 0.75 = 1440 watt-hours. So, only 1440 watt-hours of useful work would be accomplished by the motor in this 8-hour period.