I dont really understand how I can solve for x in this equation
log5^x=-2
if the log is base 10, then
log 5^x = -2
x log5 = -2
x = -2/log5
if you meant log base 5, then the definition of log gives you
x = 5^-2 = 1/25
log5^x=-2
log 5^x = -2
x log5 = -2
x = -2/log5
if you meant log base 5, then the definition of log gives you
x = 5^-2 = 1/25