Two similar solids whose densities are each 1g/cm³ are such that the first has a height of 5cm and a volume of 120cm³ .the second has mass of 3240g. Find the height of the second solid

volume of similar objects are proportional to the cube of the corresponding sides

x^3/5^3 = 3240/120
x^3 = 5^3*27
x = 5*3 = 15

Did you know?

Did you know that the height of a solid can be found using its mass and density? In this scenario, we have two similar solids with densities of 1g/cm³. The first solid has a height of 5cm and a volume of 120cm³. By using the formula density = mass/volume, we can determine that the mass of the first solid is 120g. Now, let's find the height of the second solid. We are given that the mass of the second solid is 3240g. Since the density of both solids is the same, we can use the same formula to find the volume of the second solid. Rearranging the formula, we have volume = mass/density. Plugging in the values, we find that the volume of the second solid is 3240cm³. To find the height of the second solid, we use the formula volume = base area x height. Since the base area is the same for both solids, we can set up the equation 120cm³ = base area x height. Solving for the height, we find that the height of the second solid is 27cm. So, did you know that the height of the second solid is 27cm based on its mass and the fact that it has the same density as the first solid?