A ball is thrown vertically upward with a speed of 12.0 m/s inside a bus moving at 9.0 m/s. What is the velocity of the ball as observed by a man standing on the street?
To calculate the velocity of the ball as observed by a man standing on the street, we need to consider the velocities of both the bus and the ball.
Let's assume that the upward direction is positive.
Given:
Velocity of the ball relative to the ground (V_ball)= 12.0 m/s (upward)
Velocity of the bus (V_bus) = 9.0 m/s (forward)
To find the velocity of the ball as observed by the man, we need to find the resultant velocity of the ball with respect to the ground. We can do this by adding the velocity of the ball relative to the bus to the velocity of the bus.
Velocity of the ball relative to the ground (V_ball_ground) = V_ball + V_bus
V_ball_ground = 12.0 m/s (upward) + 9.0 m/s (forward)
V_ball_ground = 21.0 m/s (upward and forward)
Therefore, the velocity of the ball as observed by the man standing on the street is 21.0 m/s in the upward and forward direction.