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The bearing of Q from P is 150 and the bearing of P from R is 015 if Q and R are 24km and 32km respectively from P. represent this in a diagram calculate the distance Q and R to 2dp find the correct to the nearest degree

if you do the diagram, you can see that the law of cosines will produce the desired result. You just need to determine angle P in triangle PQR

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Did you know that bearings are used to represent directions in navigation? In the given information, the bearing of point Q from point P is 150 degrees, while the bearing of P from R is 015 degrees. This means that if you were standing at point P and facing towards point Q, you would be facing 150 degrees clockwise from the north direction. Similarly, from point R, facing towards point P, you would be facing 015 degrees clockwise from the north direction. On a diagram, this can be represented as arrows originating from point P, pointing towards Q and R respectively, with the corresponding bearing angles indicated. Additionally, using the distance information provided, one can calculate that point Q is 24 kilometers away from P, and point R is 32 kilometers away from P. Calculating to 2 decimal places, the distances from Q to P and from R to P are found.