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A block of mass 2kg has a constant velocity when it is pushed along a table by a force of 5N. When force increased to 9N.what is a) the resultant force , b) the acceleration ?
1 answer
so the resisting force is 5N
(a) 9-5 = 4 N
(b) a = F/m = 4/2 = 2 m/s^2
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