14.g 14.2 g of zinc trioxocarbonate iv where heating strongly to a constant mass and the residuel treated with excess hydrochloric acid. calculate the mass of zinc chloride that will be obtained if zinc equals to 5,chloride equals 12, oxygen equals 16 hydrogen 1 equals 35.5
A correct name for ZnCO3 is zinc carbonate. The name you supplied is not recognized by the IUPAC (International Union of Pure and Applied Chemistry).
Zn + heat --> ZnO + CO2
ZnO + 2HCl ==> ZnCl2 + H2O
The numbers you have supplied for Zn, O, Cl are nuts and you didn't give one for C but I'll go along with them.I'll call C = 12. Molar mass ZnCO3 using your numbers is 5 + 12 + 3*16 = 65
moles Zn in 14.2 g using your numbers = 14.2/65 = 0.218
mols ZnCl2 formed, using your numbers,
= 0.218 mols ZnCO3 x (1 mole ZnO/1 mole Zn) x (1 mole ZnCl2/1 mol ZnCl2) = 0.218 x 1/1 x 1/1 = 0.218
Then grams ZnCl2 formed = moles ZnCl2 x molar mass ZnCl2. Using your numbers the molar mass of ZnCl2 = 5 + 12 = 17 so 0.218 x molar mass ZnCl2 = 0.218 moles x 17 g/mol = ?
I don't where you dreamed up these numbers for the atomic masses but good luck