Given (x−12 π)2+3 ≤f(x)≤ sin(x)+2 , what is limx→π/2f(x) ?
and
If f(x)={-4x+45x+8 , x≤5x>5 then find limx→5+ f(x)
This is odd. Maybe this will help.
lim(x→π/2) f(x) would be
(π/2 - 12π)^2+3 ≤ f(x) ≤ sin(π/2)+2
but that makes no sense
for the other one, since f(x) is just a polynomial, it is continuous everywhere, so just plug in x=5. Though I'm not sure just what x≤5x>5 even means
Maybe you need to retype things, which appear to be garbled.