Need help with solving.
The energy needed to vaporize a sample of water is 2.26 kj of energy per 1 gram of water. How hot would a 106 g sample of copper (specific heat = 0.385 j/g deg. c) need to be to vaporize a 1.5 g sample of water at 100 deg. c (assume the water is all in the liquid phase at this temperature, the final temp of the metal is 100 deg. c, and that all the energy goes into the phase change
How many joules do you need to vaporize 1.5 g H2O @ 100 C.
That;s 1.5 g H2O x (2.26 kJ/g) = 3.39 kJ = 3390 J.
What must the final temperature of the Cu be to provide 3390 J energy and end up @ 100 C. That's
3390 = mass Cu x specific heat Cu x (Tfinal-Tinital)
You know mass Cu, specific heat Cu and Tfinal(that's 100 C). Solve for Tinitial
Post your work if you get stuck.
Thank You.
My final answer was -16.9321. Is that correct? Would that be my final answer?