The length of a rectangle is four meters less than twice its width. If the perimeter of the rectangle is 88 meters, what is the width?
To find the width of the rectangle, we can set up an equation using the given information.
Let's say the width of the rectangle is represented by "w" meters.
According to the problem, the length of the rectangle is four meters less than twice its width. So, the length would be 2w - 4 meters.
The perimeter of a rectangle is the sum of all its sides. In this case, the perimeter is 88 meters.
Since a rectangle has two equal sides of width "w" and two equal sides of length "2w - 4", we can write the equation for the perimeter as:
Perimeter = 2 × Width + 2 × Length
Substituting our values from above, we get:
88 = 2w + 2(2w - 4)
Now, we can simplify and solve for the width:
88 = 2w + 4w - 8
Combining like terms:
88 = 6w - 8
Adding 8 to both sides:
88 + 8 = 6w
96 = 6w
Dividing both sides by 6:
16 = w
Therefore, the width of the rectangle is 16 meters.