A speeder passes a parked police car at a
constant speed of 39.7 m/s. At that instant,
the police car starts from rest with a uniform
acceleration of 2.04 m/s^2
.
How much time passes before the speeder
is overtaken by the police car?
when you have 1/2 at^2 = vt
1/2 * 2.04 t^2 = 39.7t