A number of commuters were on a bus when it started its journey form the bus station. At the first bus stop, 1/7 of the commuters got off. At the second bus stop, 1/6 of the remaining commuters got off,
so far, two stops
Let's break down the problem step by step:
Step 1: Let's assume there were C commuters at the beginning of the bus journey.
Step 2: At the first bus stop, 1/7 of the commuters got off. Since 1/7 represents the fraction that got off, the fraction that remained is 1 - 1/7 = 6/7. This means that (6/7) * C commuters remained.
Step 3: At the second bus stop, 1/6 of the remaining commuters got off. Following the same logic as above, the fraction that remained after the second bus stop is 1 - 1/6 = 5/6. Therefore, the number of commuters who remained after the second bus stop is (5/6) * (6/7) * C.
Therefore, the number of commuters who remained on the bus after the second bus stop is (5/6) * (6/7) * C.
To find the number of commuters remaining on the bus after the second bus stop, we can follow these steps:
Step 1: Let's assume that the number of commuters on the bus initially is 'x'.
Step 2: At the first bus stop, 1/7 of the commuters got off. Therefore, the number of remaining commuters will be:
x - (1/7)x
Step 3: At the second bus stop, 1/6 of the remaining commuters got off. Therefore, the number of remaining commuters after the second stop will be:
(1 - 1/6) * (x - (1/7)x)
Step 4: Simplifying step 3, we get:
(5/6) * (6/7) * x
Step 5: Further simplifying, we get:
(5/7) * x
So, the number of commuters remaining on the bus after the second bus stop will be (5/7) times the initial number of commuters 'x'.