Determine the mass of sulphur(iv) oxide obtained when 91g of oxygen reacts completely with sulphur according to the following equation: S+O2 'n SO2 (S=32,O=16)
91g = 2.84 moles of O2
add that to 2.84 moles of S
and that will be 2.84 moles of SO2. How many grams is that?