If 125 cal of heat is applied to a 60.0- g piece of copper at 25.0 ∘C , what will the final temperature be? The specific heat of copper is 0.0920 cal/(g⋅∘C) .
q = mass Cu x specific heat Cu x (Tfinal-Tinitial)
125 cal = 60.0 g Cu x 0.0920 cal/g*C x (Tfinal - 25)
Solve for Tfinal.