this is an easy question, but i kept doing this in my calculator but my answer always showed up wrong.
a = (0-(20.5 m/s))^2)/(2(1.18 (x ) 10^2 ( m) =
420.25 m^2/s^2/2.36*10^2 m = 1.7807 m/s^2
The would be the rate of deceleration needed to stop in 118 meters if the initial velocity were 20.5 m/s