A sample of 0.195g of Potassium was added to 500cm3 of cold water.When the reaction was finished ,100cm3 of 0.100mol/dm3 hydrochloric acid was added to form solution x.Calculate the number of moles of hydroxide ions formed when the potassium was added to water?
2K + 2H2O = 2KOH + H2
mols K = grams/atomic mass = 0.195/39 = 0.005
moles KOH produced = 0.005
Therefore, there are 0.005 mols OH^- formed.