How many grams of sulfosalicylic acid (mol wt = 254) are required to prepare 3%w/vsolution?
3% w/v means 3 g solute/100 mL of solution. You don't say how much you want so we'll make 100 mL.
So transfer 3 g of the acid to a 100 mL volumetric flask and add some water. Swirl until all of the solid has dissolved and add enough water to fill to the mark on the flask.
To calculate the grams of sulfosalicylic acid required to prepare a 3%w/v solution, we need to know the volume of the solution being prepared.
Here's the step-by-step process:
1. Convert the percentage solution to grams per 100 mL (w/v):
3%w/v = 3 grams per 100 mL.
2. Determine the volume of the solution being prepared. Let's assume it is 500 mL.
3. Set up a proportion to find the grams of sulfosalicylic acid needed:
(3 grams / 100 mL) = (x grams / 500 mL).
4. Now, cross-multiply and solve for "x":
(3 grams)(500 mL) = (100 mL)(x grams).
1500 grams * mL = 100x grams * mL.
Divide both sides by 100:
1500 grams / 100 = x grams.
x = 15 grams.
Therefore, to prepare a 3%w/v sulfosalicylic acid solution in 500 mL, you would need 15 grams of sulfosalicylic acid.
To calculate the number of grams of sulfosalicylic acid (SSA) needed to prepare a 3% w/v solution, we will use the following formula:
grams of SSA = (percentage w/v * volume of solution in mL * density of solvent) / 100
However, since the density of water (assuming it's the solvent) is approximately 1 g/mL, we can simplify the equation further:
grams of SSA = (percentage w/v * volume of solution in mL) / 100
Given that we want to prepare a 3% w/v solution and we don't have the volume of the solution, we can assume a volume of 100 mL for simplicity.
grams of SSA = (3% * 100 mL) / 100
grams of SSA = 3 grams
Therefore, 3 grams of sulfosalicylic acid would be required to prepare a 3% w/v solution with a volume of 100 mL.