Graph above shows the speed of a car traveling in straight line as a function of time. The car accelerates uniformly and reaches a speed V of 4.00 m/s in 8.00 seconds. Calculate the distance traveled by the car from a time of 2.10 to 6.00 seconds.
a = (4 m/s) / (8 s) = 1/2 m/s^2
at t=2.1, v = 2.1a = 1.05 m/s
so, during the 3.9 seconds in question, the car traveled
s = vt + 1/2 at^2 = 1.05*3.9 + 1/4 * 3.9^2 meters