What volume of steam is produced when 10g of propyne is burnt in excess oxygen at s.t.p with workings
To determine the volume of steam produced when 10g of propyne (C3H4) is burnt in excess oxygen at standard temperature and pressure (STP), we need to follow a few steps:
1. Write the balanced chemical equation for the combustion of propyne:
C3H4 + 4O2 -> 3CO2 + 2H2O
2. Calculate the number of moles of propyne:
Given mass = 10g
Molar mass of propyne (C3H4) = (3 * atomic mass of Carbon) + (4 * atomic mass of Hydrogen)
= (3 * 12.01 g/mol) + (4 * 1.01 g/mol)
= 36.03 g/mol + 4.04 g/mol
= 40.07 g/mol
Moles of propyne = mass / molar mass
= 10g / 40.07 g/mol
≈ 0.249 mol
3. Based on the balanced equation, we can see that for every 2 moles of propyne burnt, 2 moles of water (steam) are produced:
C3H4 + 4O2 -> 3CO2 + 2H2O
So, moles of water (steam) produced = 2 × moles of propyne
= 2 × 0.249 mol
= 0.498 mol
4. Convert moles of water (steam) to volume at STP:
At STP, 1 mole of any gas occupies 22.4 liters.
So, volume of water (steam) produced = moles of water (steam) × 22.4 L/mol
= 0.498 mol × 22.4 L/mol
= 11.15 L (rounded to two decimal places)
Therefore, when 10g of propyne is burnt in excess oxygen at STP, approximately 11.15 liters of steam would be produced.