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If a boy walks 5m due West and 6m due south.

1.The magnitude of his displacement
2.The direction of his displacement

√(5^2+6^2)

WθS where tanθ = 6/5

Did you know?

Did you know that the magnitude of displacement refers to the length or distance between the starting and ending points of an object's motion? In this scenario, if a boy walks 5m due West and 6m due South, his displacement can be calculated using the Pythagorean Theorem. By squaring both distances, adding them together, and taking the square root of the sum, we find that the magnitude of his displacement is approximately 7.81m. Furthermore, the direction of his displacement can be determined by using trigonometric functions. In this case, the boy's displacement forms a right triangle, with 5m as the adjacent side (West) and 6m as the opposite side (South). By finding the inverse tangent of the opposite divided by the adjacent, we can determine that the direction of his displacement is approximately 50.19 degrees South of West.