A stone of mass 0.7kg is projected vertically upward with a speed of 5m/s calculate the maximum height reached (g=10m/s)and neglect air resistance
To calculate the maximum height reached by the stone, we can use the kinematic equation for vertical motion.
The relevant equation for vertical motion is:
vf^2 = vi^2 + 2ad
where:
- vf is the final velocity (which is 0, as the stone reaches its maximum height)
- vi is the initial velocity (5 m/s)
- a is the acceleration due to gravity (-10 m/s^2, negative because it acts in the opposite direction to the stone's motion)
- d is the displacement, or the maximum height we want to find
Rearranging the equation, we have:
d = (vf^2 - vi^2) / (2a)
Since vf is 0, the equation simplifies to:
d = -vi^2 / (2a)
Plugging in the given values:
vi = 5 m/s
a = -10 m/s^2
d = -5^2 / (2 * (-10))
Simplifying further:
d = 25 / 20
d = 1.25 m
Therefore, the maximum height reached by the stone is 1.25 meters.