Typically, water runs through the baseboard copper tubing and, therefore, fresh hot water is constantly running through the piping. However, consider a pipe where water was allowed to sit in the pipe. The hot water cools as it sits in the pipe. What is the temprature change, ( ΔT ), of the water if 208.5 g of water sat in the copper pipe from part A, releasing 2694 J of energy to the pipe? The specific heat of water is 4.184 J/(g⋅∘C) .

Question

Typically, water runs through the baseboard copper tubing and, therefore, fresh hot water is constantly running through the piping. However, consider a pipe where water was allowed to sit in the pipe. The hot water cools as it sits in the pipe. What is the temprature change, ( ΔT ), of the water if 208.5   g  of water sat in the copper pipe from part A, releasing 2694   J  of energy to the pipe?  The specific heat of water is 4.184  J/(g⋅∘C) .

DrBob222 · Answer

q = mass H2O x specific heat H2O x delta T 2694 = 208.5 g x 4.184 J/g*C x delta T