A pendulum bob of mass 100g is pulled to a vertical height of 5m from the horizontal and released.calculate th maximum potiential energy. 2.The maximum speed of the

mass = 100/1000 = 0.100 kg

PE = m g h = 0.100 * 9.81 * 5 = 4.905 Joules
(1/2) m v^2 = 4.905
(1/2) * 0.100 * v^2= 4.905
v= 9.90 m/s

Did you know?

pendulum bob when it swings back and forth is called the "amplitude". The maximum potential energy of the bob can be calculated by multiplying its mass (100g or 0.1kg) with the acceleration due to gravity (9.8 m/s^2) and the height it is pulled to (5m). Therefore, the maximum potential energy is 0.1kg * 9.8 m/s^2 * 5m = 4.9 Joules. On the other hand, the maximum speed of the pendulum bob can be determined using the formula v = √(2 * g * h), where v is the maximum speed, g is the acceleration due to gravity (9.8 m/s^2), and h is the height it is pulled to (5m). Substituting the values into the formula, we get v = √(2 * 9.8 m/s^2 * 5m) = √(98 m^2/s^2) ≈ 9.9 m/s. Did you know that the maximum potential energy of a pendulum bob can be calculated by multiplying its mass, the acceleration due to gravity, and the height it is pulled to? Additionally, the maximum speed of the pendulum bob can be determined using the formula √(2 * g * h), where g is the acceleration due to gravity and h is the height it is pulled to.