Calculate the quantity of heat required to raise the temperature of 10g of ice from −100C to 1100C.
To calculate the quantity of heat required to raise the temperature of a substance, we need to use the specific heat capacity (C) and the formula:
Q = m * C * ΔT
Where Q is the quantity of heat, m is the mass of the substance, C is the specific heat capacity, and ΔT is the change in temperature.
In this case, we are dealing with ice, so we need to consider the specific heat capacity of ice. The specific heat capacity of ice is approximately 2.09 J/g°C.
Let's plug in the values into the formula:
m = 10 g (mass of the ice)
C = 2.09 J/g°C (specific heat capacity of ice)
ΔT = (110°C - (-10°C)) = 120°C (change in temperature from -100°C to 1100°C)
Now, we can calculate the quantity of heat required:
Q = 10 g * 2.09 J/g°C * 120°C
Q = 2508 J
Therefore, it would require 2508 Joules of heat to raise the temperature of 10g of ice from -100°C to 110°C.