A 2kg brick is at rest on a table. It requires a force of 8N to set the brick sliding. A 1kg mass is placed on top of the brick. What force will be required to start it sliding?
F=ma
a=F/m
a=8/2
a=4m/s^2
F=(2+1)4
F=12N
a=F/m
a=8/2
a=4m/s^2
F=(2+1)4
F=12N