A block whose weight 45.0 N rest on a horizontal table. A horizontal force of 36.0 N is applied to the block. The coefficients of static and kinetic frictions are 0.65 and 0.42 respectively. Will the block move under the influence of the force, and if so, what will be the block's acceleration?
static friction force = 45 * .65 = 29.25 Newtons
36 - 29.25 is positive so it moves
then
kinetic friction force = 45 * .42 = 18.9 Newtons
36 - 18.9 = 17.1 Newtons
a = F/m = 17.1 / (45/9.81) = 3.73 m/s^2