Meldrick had some jellybeans. He used 185 g of them to decorate a
cake. He packed the remaining jellybeans equally into 9 identical boxes. Each box of jellybeans weighed 35 g. What was the mass of jellybeans Meldrick had at first?
9*35 + 185 = ___ g
185+9×35
185+315
500 jellybeans
Let's denote the mass of jellybeans Meldrick had initially as "x" grams.
Meldrick used 185 g of jellybeans to decorate the cake, so the remaining mass of jellybeans is x - 185 g.
He packed the remaining jellybeans into 9 identical boxes, with each box weighing 35 g.
Therefore, the mass of jellybeans in the boxes is 9 * 35 g = 315 g.
Since the remaining mass of jellybeans is equal to the mass in the boxes, we can set up the equation:
x - 185 g = 315 g
To find the value of x, we can add 185 g to both sides of the equation:
x = 315 g + 185 g
Simplifying this expression, we find:
x = 500 g
So, the mass of jellybeans Meldrick had initially was 500 grams.
To find the mass of jellybeans Meldrick had at first, we need to do some calculations.
Let's assume the mass of jellybeans Meldrick had at first is 'x' grams.
First, Meldrick used 185 g of jellybeans to decorate a cake. So, the remaining jellybeans he had is x - 185 g.
Next, Meldrick packed the remaining jellybeans equally into 9 identical boxes, with each box weighing 35 g.
The total weight of the jellybeans in the boxes is 9 * 35 g = 315 g.
Since the remaining jellybeans and the jellybeans in the boxes have the same mass, we can set up an equation:
x - 185 g = 315 g
Now, let's solve for 'x':
x = 315 g + 185 g
x = 500 g
Therefore, the mass of jellybeans Meldrick had at first was 500 grams.