The density of concentrated ammonia which is 28.0% w/w NH³ is 0.899 g/ml what valume of this reagent should be diluted to 1.0×10³ml to make a solution that is 0.036 m in NH³
I will assume you mean 0.036 M and not 0.036 m. M stands for molarity; m stands for molality They aren't the same.
First, what is the M of the 28.0% stuff.
0.899 g/mL x 1000 mL x (28 g/100 g) x (1 mol/17 g) = ? Molarity which I will call Mo for original molarity. The diluted solution we will call Mdil.
Then Mo x mLo = Mdil x mLdil
Mo from above x mLo = 0.036 M x 1000 mL
Solve for Mo, pipet that amount into a 1000 mL volumetric flask and add distilled water to the mark on the flask. Stopper, mix thoroughly, label, done.