A PARTICLE IS PROJECTED HORIZONTALLY AT 15m/s^1 FROM A HEIGHT OF 20m. CALCULATE THE HORIZONTAL DISTANCE COVERED BY THE PARTICLE JUST BEFORE HITTING THE GROUND.(g=10m/s^2).
Maximum height= 1/2gt^2
20= 1/2×10t^2
20=5t^2
4=t^2 square root both sides
t=2 seconds
R=ut
R=15×2
R=30m
s=1/2gt^2
20= 1/2×10t^2
20=5t^2
4=t^2 square root both sides
t=2 seconds
R=ut
R=15×2
R=30m