there are 51 students in a certain class. the number of females is 5 less than three times the number of males. find the number of females and the number of males in the class.
If there are x males, then
x + 3x-5 = 51
Now finish it off
Let the number of males=x
females=3x-5
x+3x-5=51
4x-5=51
4x=51+5
4x=56
x=14
females=3×14-5= 37
therefore, there are 14 males and 37 females
Let the number of males=x
females=3x-5
x+3x-5=51
4x-5=51
4x=51+5
4x=56
x=14
females=51-14=37
therefore, there are 14 males and 37 females
To solve this problem, we can use algebraic equations.
Let's assume the number of males in the class is x.
According to the problem, the number of females is 5 less than three times the number of males.
Therefore, the number of females in the class can be represented as 3x - 5.
Now, we can set up an equation using the given information. The sum of females and males is equal to the total number of students in the class, which is 51.
x + (3x - 5) = 51
Now, we can solve this equation:
4x - 5 = 51
Adding 5 to both sides:
4x = 56
Finally, divide both sides by 4:
x = 14
We have found that the number of males in the class is 14.
To find the number of females, substitute the value of x back into the equation:
3x - 5 = 3(14) - 5 = 42 - 5 = 37
Therefore, there are 37 females in the class.