An object weighs 0.48N in air and 0.18 when immersed in water . Calculate the apparent weight of the solid when immersed in a liquid of density 900kgm-3(density of water=1000kgm-3)
To calculate the apparent weight of the solid when immersed in a liquid of density 900 kg/m³, you need to consider the buoyant force acting on the object.
The buoyant force on the object can be determined using the Archimedes' principle, which states that the buoyant force on an object submerged in a fluid is equal to the weight of the fluid displaced by the object.
First, let's calculate the weight of the fluid displaced by the object when immersed in water. Since the density of water is 1000 kg/m³, the weight of the fluid displaced is equal to the volume of the object multiplied by the density of water multiplied by the acceleration due to gravity (9.8 m/s²).
Let's assume the volume of the object is V. Therefore, the weight of the fluid displaced in water is given by:
Weight_displaced_water = Volume * Density_water * Gravity
Weight_displaced_water = V * 1000 kg/m³ * 9.8 m/s²
Now, let's calculate the weight of the fluid displaced by the object when immersed in the liquid of density 900 kg/m³.
Weight_displaced_liquid = V * 900 kg/m³ * 9.8 m/s²
The apparent weight (W_apparent) of the object when immersed in the liquid is then given by the weight of the object in air minus the weight of the fluid displaced by the object when immersed in the liquid:
W_apparent = Weight_in_air - Weight_displaced_liquid
Now, let's substitute the given values into the equations:
Weight_displaced_water = V * 1000 kg/m³ * 9.8 m/s²
Weight_displaced_liquid = V * 900 kg/m³ * 9.8 m/s²
W_apparent = 0.48 N - Weight_displaced_liquid
To solve the problem, we need the volume of the object. Unfortunately, the given information doesn't provide the volume directly. If the volume is given, you can substitute it into the equations above to find the apparent weight.